Integrate 2x^4 - 4/sqrt(x) + 3 dx
First we will simplify 4/sqrt(x) so it is easier to integrate.sqrt(x) is equal to x1/2, therefore 4/sqrt(x) = 4/x1/2 .We bring up x1/2 so 4/x1/2 becomes 4x-1/2 .So now we will integrate the simplified equation 2x4 - 4x-1/2+ 3.To integrate we add one to the power and divide by the new power. To numbers without an x, we add an x.Therefore we get 2x5/5 - 4x1/2/(1/2) + 3x + c.Simplified this is, 2/5x5 - 8x1/2 + 3x + c.When integrating, always remember to add c, this represents a constant.
MA
Related Maths A Level answers
All answers ▸integrate( x^3+4x^2+3)dx
differentiate 2^x
Differentiate y = x^3 + 2x^2 + 4x + 3
Three forces, (15i + j) N, (5qi – pj) N and (–3pi – qj) N, where p and q are constants, act on a particle. Given that the particle is in equilibrium, find the value of p and the value of q. (Mechanics 1 June 2017)