Integrate 2x^4 - 4/sqrt(x) + 3 dx
First we will simplify 4/sqrt(x) so it is easier to integrate.sqrt(x) is equal to x1/2, therefore 4/sqrt(x) = 4/x1/2 .We bring up x1/2 so 4/x1/2 becomes 4x-1/2 .So now we will integrate the simplified equation 2x4 - 4x-1/2+ 3.To integrate we add one to the power and divide by the new power. To numbers without an x, we add an x.Therefore we get 2x5/5 - 4x1/2/(1/2) + 3x + c.Simplified this is, 2/5x5 - 8x1/2 + 3x + c.When integrating, always remember to add c, this represents a constant.
MA
Related Maths A Level answers
All answers ▸The curve C has equation y = f(x) where f(x) = (4x + 1) / (x - 2) and x>2. Given that P is a point on C such that f'(x) = -1.
a) Solve the following equation by completing the square: x^(2)+ 6x + 1= 0. b) Solve the following equation by factorisation: x^(2) - 4x - 5 = 0 c) Solve the following quadratic inequality: x^(2) - 4x - 5 < 0 (hint use your answer to part b)
Find the area under the curve with equation y = 5x - 2x^2 - 2, bounded by the x-axis and the points at which the curve reach the x-axis.
How many lines of method should I write in order to get all of the marks?