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Solve by completing the square: x^2 - 8x + 12 = 0

x 2 - 8x + 12 = 0 (x - 4) 2 - 16 + 12 = 0 (x - 4) 2 - 4 = 0 (x - 4) 2 = 4 x - 4 = +- 2 x = 6 x = 2
JV
Answered by Julianna V. • Maths tutor
4682 Views

Consider the functions f(x) = −x^3 + 2x^2 + 3x and g(x) = −x^3 + 3x^2 − x + 3. (a) Find df/dx (x) and hence show that f(x) has turning points at when x = 2 /3 ± √ 13/ 3 . [5] (b) Find the points where f(x) and g(x) intersect. [4]

a) First differentiate f(x) using standard polynomial derivative rules which gives, df/dx=-3x^2+4x+3. The derivative function gives the gradient of f for any value of x. Turning points occur when the gradien...
GA
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Solve the following: sinx - cosx = 0 for 0≤x≤360

We know that sinx/cosx = tanx. Therefore we can write sinx - cosx = 0 as sinx = cosx . By diving both sides by cosx, we get tanx = 1. By taking tan inverse of both sides, we can see that for 0≤x≤360, we get ...
AK
Answered by Aaman K. • Maths tutor
17564 Views

Solve the following quadratic equation for X: X^2 -10X + 24=0

We can factorise the quadratic equation by noting that two numbers which multiply to get 24 and that add to get -10 are: -6 and -4. Therefore, we get (X-6)(X-4)=0 and we can solve for X to get X = 6 or X = 4.
AK
Answered by Aaman K. • Maths tutor
4069 Views

I'm good at maths, I swear

I don't know what gcse entails but I'm certain I could teach it
RA
Answered by Ross A. • Maths tutor
3824 Views