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Find the equation of the normal to the curve at the point (1, -1 ): 10yx^2 + 6x - 2y + 3 = x^3

Firstly, an expression for dy/dx needs to be found to allow us to find the gradient of the normal. As a normal is a straight line, the equation y-y 1 =m(x-x 1 ) can be used to find its equation. We are given...
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Answered by Tutor125302 D. • Maths tutor
5609 Views

How to solve a simultaneous equation?

In simultaneous equations, at this level, you are often given two equations both containing an x and a y. For example:Equation1: y + 2x = 3Equation2: 4y + 2x = 8.The first step in approaching this is to try ...
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Answered by Sophie B. • Maths tutor
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Express x^2-4x+9 in the form (x-p)^2+q where p and q are integers

The first step would be to expand the second equation:(x-p)^2+qx^2-px-px+p^2+q this simplifies to x^2-2px+p^2+q After this you examine the two equations and identify their similarities such as the x^2 term a...
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Answered by Mark N. • Maths tutor
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Given that y = 2^x, express 4^x in terms of y.

4^x = (2*2)^x =2^x * 2^x = y^2
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Answered by Benjamin M. • Maths tutor
14865 Views

Solve the inequality 􏰂|2x + 1|􏰂 < 3|􏰂x − 2|􏰂.

(2x+1) 2 &lt; 9(x-2) 2 4x 2 +4x+1 &lt; 9(x 2 -4x+4)4x 2 +4x+1 &lt; 9x 2 -36x+360 &lt; 5x 2 -40x+35Apply quadratic equation solving formula (40+30)/10=7 and (40-30)/10=1hence x&lt;1 and x&gt;7
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Answered by Alejandra T. • Maths tutor
10014 Views