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Solve the inequality 􏰂|2x + 1|􏰂 < 3|􏰂x − 2|􏰂.

(2x+1)²< 9(x-2)²4x²+4x+1 < 9(x²-4x+4)4x²+4x+1 < 9x²-36x+360 < 5x²-40x+35Apply quadratic equation solving formula (40+30)/10=7 and (40-30)/10=1hence x<1 and x>7

Answered by Alejandra T. • Maths tutor

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Solve the inequality 􏰂|2x + 1|􏰂 < 3|􏰂x − 2|􏰂.

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Express 5cosx - 3sinx in the form Rcos(x+a).

Expand using binomial expansion (1+6x)^3

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