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Find the coordinates of the point of intersection of the lines 2x + 3y = 12 and y = 7 - 3x.

We can substitute the equation for y into 2x + 3y = 12. If y = 7-3x , 2x + 3(7-3x) = 12 2x + 21-9x = 12 Now we can solve for x -7x = =-9x = 9/7 To get y, we must sub x back into y = 7 - 3x, to get the y co-o...
CA
Answered by Chrystine A. Maths tutor
8892 Views

Integrate (1 - x^2)^(-0.5)dx within the limits 0 and 1

The answer is π/2. The key trick to solving this problem is to change variables by using the substitution x = sin(θ). We then need to change the differential and the limits too.
CW
Answered by Cameron W. Maths tutor
4192 Views

A right-angled triangle has perpendicular sides of length 6cm and 8cm, and a hypoteneuse of 2y cm. Find the length of y.

By Pythagoras' Theorem:(2y) 2 = 6 2 + 8 2 4y 2 = 36 +64y 2 = 9 + 16y 2 = 25y = ±5However, dimensions can only have a positive value. Therefore y=5
ES
Answered by Emmanuel S. Maths tutor
3307 Views

Solve the simultaneous equations to find x and y: 3y - x = 12 y + 2x = -3

3y - x = 12 (1)y + 2x = -3 (2)multiply equation (2) by 3: 3y + 6x = -9 (3)subtract equation (1) from equation (3): 3y + 6x - 3y + x = -9 -12 7x = -21 x = -3substitute x into equation (2): y -6 = -3 y = 3answ...
CG
Answered by Chloe G. Maths tutor
4494 Views

Differentiate y = x^3− 5x^2 + 3x

the rule for differentiating in terms of x is to multiply by the power then decrease the power by one. So going through the equation x^3 will be multiplied by 3 and go to x^2 so will be 3x^2. Then its import...
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Answered by Georgia D. Maths tutor
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