Expand the following quadratic expression: (2x+4)(x-5)

Multiply the first terms in both brackets:2xx= 2x2
Next multiply the first term of the first bracket and the second term of the second bracket:2x
-5= -10x
Multiply the second term of the first bracket with the first term of the second bracket:4x= 4x
Multiply the second terms of both brackets:4
-5= -20
So now there is the expression: 2x2-10x+4x-20Add up the two 'x' terms to get the final quadratic: 2x2-6x-20

MP
Answered by Meera P. Maths tutor

5589 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Solve 5(x-6) < 20


Solve simultaneously, 2x-3y=16 and x+2y=-6


How can I use the Pythagoras' Theorem to work out the length of a missing side of a triangle?


how should i revise maths, since there aren't many notes and its mainly applied?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning