Expand the following quadratic expression: (2x+4)(x-5)
Multiply the first terms in both brackets:2xx= 2x2
Next multiply the first term of the first bracket and the second term of the second bracket:2x-5= -10x
Multiply the second term of the first bracket with the first term of the second bracket:4x= 4x
Multiply the second terms of both brackets:4-5= -20
So now there is the expression: 2x2-10x+4x-20Add up the two 'x' terms to get the final quadratic: 2x2-6x-20
MP
Related Maths GCSE answers
All answers ▸what is the point of intersection between the lines 3y-4x=12 and 2x=2y+3
Solve the inequality x^2 + 5x -24 ≥ 0.
Solve for x: y=x^2-x-12
y is directly proportional to (d+2)^2, when d=5, y=147. d^2 is inversely proportional to x^2, when d=2, x=3. Find an equation for y in terms of x