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A motorist traveling at 10m/s, was able to bring his car to rest in a distance of 10m. If he had been traveling at 30m/s, in what distance could he bring his cart to rest using the same breaking force?

By just a quick look you might be tempted to say 30 m. However the key information is that the breaking force is the same. We can calculate the deceleration of the car when at 10m/s using the equation of mot...
CT
Answered by Charis T. • Physics tutor
22789 Views

A car is moving along a straight horizontal road, with a constant acceleration. The car passes point A, with a speed of ums(-1). 10 seconds later, passes point B, with a speed of 45 ms(-1). The distance from A to B is 300m. Find u.

Here, we must consider our UVAST equations of motion, and our variables. U=?ms^(-1), V=45ms^(-1) , A=?ms^(-2), S= 300m, T=10s Our equations of motion are: V = U + AT , S = (1/2)(V+U)T , S = UT + (1/2)AT^2 , ...
AM
Answered by Alice M. • Physics tutor
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A sequence is defined by the recurrence relation u(n+1) = 1/3 u(n) + 10 with u(3) = 6 . Find the value of u(4) and the limit of the sequence.

A sequence is defined by the recurrence relation u n+1 = 1/3 u n + 10 with u 3 = 6 . Find the value of u 4 and the limit of the sequence. To find the value of u 4 we replace u n by u 3 in the equation and th...
DS
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How much work must be done on a 4.0kg frictionless trolley, to accelerate it from rest to a velocity of 5.0m/s?

It must firstly be noted that, in general, the work done on an object is equal to its gain in energy.The trolley has gained kinetic energy. This can be calculated using the formula: "KE = (1/2)mv^2&quot...
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Answered by Will W. • Physics tutor
3583 Views

How would I resolve forces on a slope?

First pick a set of axis to use. This would be in the directions of which the majority of the forces follow. With the forces which are at angles to the majority of the forces, create a triangle of the horzio...
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Answered by George B. • Physics tutor
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