How much work must be done on a 4.0kg frictionless trolley, to accelerate it from rest to a velocity of 5.0m/s?

It must firstly be noted that, in general, the work done on an object is equal to its gain in energy.The trolley has gained kinetic energy. This can be calculated using the formula: "KE = (1/2)mv^2" where 'm' is the mass of the object and 'v' is its new velocity, when accelerating from rest.The KE gained by the trolley = (1/2) m v^2                              = (1/2) x 4 x 5^2                              = 50 JSo the work done on the trolley is equal to 50J.

WW
Answered by Will W. Physics tutor

3204 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Two students are provided with a starting pistol, a stopwatch and a long measuring tape. The starting pistol produces a loud sound and a puff of smoke. Describe how the students use the apparatus to calculate the speed of sound.


What is the difference between alpha and gamma radiation?


A motor does 4.8kJ of work in 2 minutes. What is its power output?


What is the wavelength of a wave?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning