How much work must be done on a 4.0kg frictionless trolley, to accelerate it from rest to a velocity of 5.0m/s?

It must firstly be noted that, in general, the work done on an object is equal to its gain in energy.The trolley has gained kinetic energy. This can be calculated using the formula: "KE = (1/2)mv^2" where 'm' is the mass of the object and 'v' is its new velocity, when accelerating from rest.The KE gained by the trolley = (1/2) m v^2                              = (1/2) x 4 x 5^2                              = 50 JSo the work done on the trolley is equal to 50J.

WW
Answered by Will W. Physics tutor

2858 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Photons with 605 THz frequency strike metal of 1.2eV work function. Calculate the maximum energy of photoelectrons and their velocity. What amount of energy is necessary to stop all photoelectrons? (Planck's constant. electron mass and charge are given)


Why is the nuclear model better than the plum pudding model of the atom?


Sophia (mass 47Kg) is travelling to the right with a velocity of 7.2m/s and ​Neesha (mass 68Kg) is travelling to the left with a velocity 4.8m/s. When ​they meet, they hold hands and travel off together. Give their final ​velocity and direction


How do I use equations of motion ('suvat') to find a missing quantity?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences