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A circle with equation x^2+y^2-2x+8y-40=0. Find the circle centre and the radius

2g=-2, -g=1. 2f=-8, -f=4. cc(-2,4). r=√(g^2+f^2-c)=√(4+16+40)=√80=4√5
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Answered by Liam M. • Maths tutor
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How do you create the future tense of a russian verb?

This depends on whether your verb is imperfective or perfective. IMPERFECTIVE FUTURE For imperfective verbs, the future tense can be constructed, just like in English, by using the correct form of "быть...
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Answered by Bethany B. • Russian tutor
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Integrate ∫x^4+5x^3+sin(2x) dx

∫x^4+5x^3+sin(2x) dx So a basic rule for x functions is that 1. Add 1 to the power 2. divide by the new power. So lets do this for the 2 x terms 1/5x^5+5/4 x^4 Now lets look at the sin(2x). A general rule fo...
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Answered by Liam M. • Maths tutor
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A line joins 2 points (2,9) and (5,4). Calculate the gradient of the straight line and then write down the equation of the straight line.

The first thing to do is to look at the points given and decide if you are going to get a negative or positive gradient. We can determine, from inspection that the gradient will be negative because as the x ...
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Answered by Liam M. • Maths tutor
5471 Views

Find the roots of 2x^2-5x-6=0 to 3dps

if we see the phrase "to N dps" this is a big hint to use the quadratic formula. The first thing we have to do is to is pick out the co-efficients ax^2+bx+c=0 a=2, b=-5, c=-6 Now we can pug these n...
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Answered by Liam M. • Maths tutor
4971 Views