Find the roots of 2x^2-5x-6=0 to 3dps

if we see the phrase "to N dps" this is a big hint to use the quadratic formula. The first thing we have to do is to is pick out the co-efficients ax^2+bx+c=0 a=2, b=-5, c=-6 Now we can pug these numbers into the quadratic formula x=(-b±√(b^2-4ac))/2a x=(5±√(25-42-6))/4 x=(5±√(25+48))/4 x=(5±√73)/4 x=3.386,-0.886 (3dps)

LM
Answered by Liam M. Maths tutor

4395 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Factorise the equation x^2 + 5x+6 = 0


Solve the quadratic function x^2 + 3x + 2


The diagram shows a sector ORST of a circle with centre O. OR = OT = 10.4 cm. Angle ROT = 120°. (a) Calculate the length of the arc RST of the sector (3s.f)


Write 32 X 8^(2x) as a power of 2 in terms of x.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning