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Step 1: Work out the moles of NaOH and HCl added into the solution 10cm^3 of 1M NaOH would mean that there is 10cm^3/1000cm^3 x 1M present, i.e. 0.01 moles 15cm^3 of 0.5M HCl would mean that there is 15cm^3/...

We want a solution to ax^2+bx+c=0. Complete the square to get a[(x+b/2a)^2 -(b^2)/(4a^2)]+c=0. Expalding brackets and rearanging gets a(x+b/2a)^2=(b^2)/4a -c. Divide by a to get (x+b/2a)^2= b^2/4a^2 -c/a=(b^...

Let’s break this down. Let’s look at how much time you have before the exam and work out something manageable, because overwhelming yourself with too much revision can be counter productive. The question I a...

First thing’s first, let’s take a look at the AQA mark scheme, because that is what your marker will be following when they get your completed paper. The first thing they talk about in their mark scheme is w...

We start with the definitions of sine and cosine, which are, respectively: sinx = opposite/hypoteneuse and cosx = adjacent/hypoteneuse. We then square the analyzed expressions to get the following: (opposite...