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Using the substitution of u=6x+5 find the value of the area under the curve f(x)=(2x-3)(6x+%)^1/2 bounded between x=1 and x=1/2 to 4 decimal places.

dx=du/6 => (u-5)/6=x So the integral is now (2((u-5)/6)-3)(u^1/2) du/6 Which through simplifying becomes (1/36)(2u-28)(u^1/2)du = (1/36)(2u^3/2 -28u^1/2)du After integrating becomes (1/36)(4(u^5/2)/5 -56(...
JT
Answered by Joseph T. • Maths tutor
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Solve the equation to find the value of t. (5t+3)/4=1

Step 1: (5t+3)/4 = 1 Step 2: (5t+3)= 1 x 4 Step 3: 5t + 3 = 4 Step 4: 5t = 4 - 3 Step 5: 5t = 1 Answer: t = 1/5
BM
Answered by Bhavya M. • Maths tutor
6418 Views

How do I compare two texts of different genres in an essay?

Comparing texts of different genres can sometimes seem daunting, but is easier than you think. The most effective way to make the comparison is to think about the theme, or themes, that you are comparing the...
OC
Answered by Oliver C. • English tutor
18150 Views

What is the best way to revise for a Maths A-level?

The best method to revise is through solving past questions and timed exam papers. As long as you have your notes and understand all the basic principles, then you just need to practice in order to avoid get...
AE
Answered by Ayah E. • Maths tutor
8939 Views

Integration by parts: Integrate the expression x.ln(x) between 1 and 2.

Let $ denote the integral symbol, as I am limited here by my keyboard. Recall the formula for integration by parts: $ u.(dv/dx) dx = uv - $ u(dv/dx) dx So to find $ pi 0 x.sin(x) dx, we must allocate x and s...
RH
Answered by Rebecca H. • Maths tutor
3648 Views