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We want a solution to ax^2+bx+c=0. Complete the square to get a[(x+b/2a)^2 -(b^2)/(4a^2)]+c=0. Expalding brackets and rearanging gets a(x+b/2a)^2=(b^2)/4a -c. Divide by a to get (x+b/2a)^2= b^2/4a^2 -c/a=(b^...

Let’s break this down. Let’s look at how much time you have before the exam and work out something manageable, because overwhelming yourself with too much revision can be counter productive. The question I a...

First thing’s first, let’s take a look at the AQA mark scheme, because that is what your marker will be following when they get your completed paper. The first thing they talk about in their mark scheme is w...

We start with the definitions of sine and cosine, which are, respectively: sinx = opposite/hypoteneuse and cosx = adjacent/hypoteneuse. We then square the analyzed expressions to get the following: (opposite...

The knowledge argument purports to show that the human mind is not a physical thing by showing that no amount of physical information can capture all the information there is about it. It invites us to consi...