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Integrate y=x^2 between the limits x=3 and x=1

Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3
CW
Answered by Caleb W. • Maths tutor
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Given that y=((3x+1)^2)*cos(3x), find dy/dx.

As why is in the for y=uv where u and v are funtions of x, dy/dx=u'v+v'u (where ' implies the derivative) u=(3x+1) 2 , v=cos(3x) therefore using the chain rule u'=2 3 (3x+1)=18x+6 and v'=-3sin(3x). Using thi...
WR
Answered by William R. • Maths tutor
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What is your understanding of the 7 day NHS?

There are two strands to the policy. Firstly, they want local GP surgeries to open on a Saturday and Sunday. They do not expect every surgery to be open and instead have urged GPs to work together with other...
FT
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What are the consequences of a 7 day NHS?

1) Leaked governmental plans highlighted the lack of funding and detailed plans for the seven day NHS, causing more doctors to raise concerns. 2) GPs have questioned whether opening surgeries for routine car...
FT
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x^2 - 10x + 33 ≡ (x - a)^2 + b. Work out the value of a and b.

x 2 - 10x + 33 ≡ (x - a ) 2 + b Work out the value of a and b . Our aim here is to write the expression on the left in the same form as the one on the right so that we can compare the two. Therefore, conside...
JC
Answered by Joshua C. • Maths tutor
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