Integrate y=x^2 between the limits x=3 and x=1
Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3
CW
Related Maths A Level answers
All answers ▸Find the equation of the tangent to the curve y^3 - 4x^2 - 3xy + 25 = 0 at the point (2,-3).
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How do you rationalise the denominator?
Use integration by parts to find the integral of ln x by taking ln x as the multiple of 1 and ln x