Integrate y=x^2 between the limits x=3 and x=1
Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3
CW
Related Maths A Level answers
All answers ▸Why do we have to add the +c when integrating a function
It is given that n satisfies the equation 2*log(n) - log(5*n - 24) = log(4). Show that n^2 - 20*n + 96 = 0.
Differentiate with respect to x: y=(6x^2-1)/2sqrt(x)
A curve has parametric equations x = 2 sin θ, y = cos 2θ. Find y in terms of x