Integrate y=x^2 between the limits x=3 and x=1

Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3

CW
Answered by Caleb W. Maths tutor

3562 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Given y = x^3 + 4x + 1, find the value of dy/dx when x=3


Find the constant term in the expression (x^2-1/x)^9


Prove algebraically that n^3 +3n -1 is odd for all positive integers n


Find the coordinates of the minimum point on the curve: y = x^2 - x - 2


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences