Given that y=((3x+1)^2)*cos(3x), find dy/dx.

As why is in the for y=uv where u and v are funtions of x, dy/dx=u'v+v'u (where ' implies the derivative) u=(3x+1)2, v=cos(3x) therefore using the chain rule u'=23(3x+1)=18x+6 and v'=-3sin(3x). Using this, dy/dy=(18x+6)*cos(3x)-3(3x+1)2*sin(3x)

WR
Answered by William R. Maths tutor

3355 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

A curve with equation y=f(x) passes through the point (1, 4/3). Given that f'(x) = x^3 + 2*x^0.5 + 8, find f(x).


Let p(x) =30x^3 - 7x^2 -7x + 2. Prove that (2x+1) is a factor of p(x).


Solve 8(4^x ) – 9(2^x ) + 1 = 0


Find the value of x in (4^5⋅x+32^2)⋅2^5=2^16⋅x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences