Given that y=((3x+1)^2)*cos(3x), find dy/dx.

As why is in the for y=uv where u and v are funtions of x, dy/dx=u'v+v'u (where ' implies the derivative) u=(3x+1)2, v=cos(3x) therefore using the chain rule u'=23(3x+1)=18x+6 and v'=-3sin(3x). Using this, dy/dy=(18x+6)*cos(3x)-3(3x+1)2*sin(3x)

WR
Answered by William R. Maths tutor

3449 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Which value of x gives the greatest value of "-x^2+8x-6"


Find the indefinite integral of Ln(x)


differentiate 4x^3 + 3x^2 -5x +1


a) show that (cosx)^2=8(sinx)^2-6sinx can be written as (3sinx-1)^2=2 b)Solve (cosx)^2=8(sinx)^2-6sinx


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences