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Factorise 4xy-6xz

Method First Look for a term (i.e x , y, z) which is in all the compoents Also look if there is a possible common factor that the compoents share Soloution ​x is a shared term , and 2 is a common multiple Th...
CT
Answered by Cameron T. Maths tutor
10184 Views

Make a the subject of the following equation, p=(3a+5)/(4-a)

In this question I would initially aim to get an a on both sides of the equation. My first step would be to multiply both sides by (4-a) to do this. After this point I would expand out the brackets on the le...
MO
Answered by Martin O. Maths tutor
8285 Views

Derive from the standard quadratic equation, the form of the quadratic solution

ax 2 +bx+c=0 : basic quadratic equation a(x 2 + bx/a) + c=0 a((x+b/2a) 2 - b 2 /4a 2 ) + c=0 (retain equation with only one x variable; compensate for b term squared out with term - b 2 /4a 2, ) a(x+b/2a) 2 ...
JD
Answered by Jaiveer D. Maths tutor
6808 Views

How to use 'ser' and 'estar'

Both ser and estar translate in English as 'to be'. Ser and estar, however, are very different in both meaning and usage. First of all it is important to note that both ser and estar are irregular verbs. For...
CS
Answered by Callum S. Spanish tutor
5581 Views

Factorise and solve: x^2 - 8x = -15

Step 1 : The first step is to rewrite the equation in the form a x 2 + b x + c = 0. So in this case, we achieve this by adding 15 to both sides: x 2 - 8x + 15 = -15 + 15 x 2 - 8x + 15 = 0 Step 2: Now we need...
MJ
Answered by Maisie J. Maths tutor
7866 Views