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multiply with conjugate 5-root3 such that the denominator gets rational (5-root3)^2/((5+root3)(5-root3)) = (25-10root3+3)/(25-3)=(28-10root3)/22 = 14/11 - 5root3/11

x^3-6x^2+9x=x(x^2-6x+9) observe binomial formula (x-3)^2=(x^2-6x+9) Thus x(x-3)^2 and the function has two points meeting the x-axis.

First step: integrate int df/dx = x^2+3x+c (never forget the constant!) Second step: substitute the point in order to get c 1 = (1)^2+3*1+c -> c = 1-1-3=-3 Thus, f = x^2+3x-3

In the IB, it is of paramount importance that one should strictly follow the subject guidelines. If you look at the marking rubric, it is important that you 1.) Effectively organise your arguments in order o...

When writing an essay, it is imperative that you close read quotations from the set text you are studying. However, this can be tricky- particurarly if you are not familiar with poetic devices, rhetoric and ...