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A curve has parametric equations: x=(t-1)^3 and y= 3t - 8/(t^2). Find dy/dx in terms of t. Then find the equation of the normal at the point on the curve where t=2.

dx/dt = 3(t-1) 2 dy/dt = 3 + 16t -3 dy/dx=(dy/dt)(dt/dx) dy/dx = 3 + 16t -3 / 3(t-1) 2 At t=2 dy/dx= (3 + 16/8) / 3 = 5/3 Gradient of the normal = -3/5with t=2 y-4=0x-1=0 y=mx + c y - 4 = -3/5(x-1) 3x +5y -2...
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Answered by Jasmin H. • Maths tutor
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Explain one reason why the global shift of industry has had negative impacts on some people in the developed world.

To answer this question for four marks, all you need to do is identify one problem caused by the global shift (for one mark) and then expand on the problems this can lead to (for a further three marks). In t...
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Answered by Esther H. • Geography tutor
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Write a piece of descriptive writing under 1000 words

Golden rays of joy radiate through time-honoured glass. Bells sing, calling to students and teachers alike. It is a cheerful Friday afternoon; an air of feverish delirium coats the school. Picturesque and we...
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How can functions be transformed?

A function, y = f(x), with y on the vertical axis and x on the horizontal axis, can be transformed by 3 different ways: It can be stretched (or shrunk)If y = f(ax), the function is stretched by a scale facto...
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Answered by Jack M. • Maths tutor
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If y = 15 + 5(x + 2), and x = 6, what is y?

Because we're told that x = 6, we can just rewrite the original equation but replace the x with a 6. So: y = 15 + 5(6 + 2) 6 + 2 = 8, so we can rewrite this again as: y = 15 + 5(8) 5(8) is just another way o...
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Answered by Alfie H. • Maths tutor
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