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A particle is moving along a straight line. The fixed point O lies on this line. The displacement of the particle from O at time t seconds is s metres where s = 2t3 – 12t2 + 7t(a) Find an expression for the velocity, v m/s, of the particle at time t.

To find velocity you differentiate displacement with respect to time Therefore ds/dt = v = (3x2)t 2 -(12x2)t 2 +7 Implying v = 6t 2 -24t+7
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Answered by Thomas O. • Maths tutor
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Give the prime factorisation of 630

630 = 5 x 126 126 = 2 x 63 63 = 7 x 9 9 = 3 x 3 so 630 = 2 x 3 2 x 5 x 7
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Answered by Annie D. • Maths tutor
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How do heterolytic catalysts work?

What are catalysts? They are substances that speed up the rate of reaction by providing a favourable pathway, of lower activation energy, for the reaction to proceed. A heterogeneous catalyst is one that is ...
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Answered by Dhylan M. • Chemistry tutor
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What is the difference between a compiler and an interpreter?

Both compilers and interpreters are used to translate high level programming languages to machine code. Compilers do this by converting all of the high level code into machine code before running the program...
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Answered by Joel P. • Computing tutor
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Find the equation of the straight line which passes through the points (3,1) and (-1,3)?

The equation of a line is y=mx+c. The first step is to find m, which is the gradient. This is found by dividing the change in the y values, by the change in x values. So in this case, the gradient would be (...
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Answered by Joel P. • Maths tutor
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