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Given that d/dx(cosx)=-sinx show that d/dx(secx)=secx(tanx)

let y=sec(x) = 1/(cos(X)) = cos(x) -1 Thus dy/dx = -1(cos(x)) -2 (-sinx) = sin(x)/(cos(x)) 2 = 1/cos(x) x sin(x)/cos(x) =sec(x)tan(x)
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Answered by Owain D. • Maths tutor
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Understanding HIV, vaccines and monoclonal antibodies

To understand how HIV causes infection, students should have an appreciation for its basic virus structure and how it infects humans. Following infection, how does it cause disease and eventually AIDS? Why a...
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Answered by Subi S. • Biology tutor
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What's the best way to revise for the Writing task of BMAT?

Here is a sample question from the writing task of the BMAT exam. 4. Parents who withhold vaccines from their children have betrayed their duty of care. How would you go about answering this? The answer is p...
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Oxbridge applications. We've all heard the rumours flying around about how your interviewers ask you to balance on your head whilst solving a simultaneous equation and reading a book. This is simply NOT true...
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How do I write a good personal statement for medicine?

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