Given that d/dx(cosx)=-sinx show that d/dx(secx)=secx(tanx)
let y=sec(x) = 1/(cos(X)) = cos(x)-1
Thus dy/dx = -1(cos(x))-2(-sinx) = sin(x)/(cos(x))2
= 1/cos(x) x sin(x)/cos(x)
=sec(x)tan(x)
OD
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