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x/(2x-3) + 4/(x+1) =1 [5 mark question]

We have 2 fractions we want to get rid off to make it easier, so what we do is multiply both sides by the things we want to get rid off.In this case we multiply both sides by (2x-3)(x+1)This gives us x(x+1) ...
AJ
Answered by Abdul Jalil A. • Maths tutor
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What is the plus-que-parfait and when do you use it?

First of all, these more complex tenses are often very complicated and difficult so do not feel discouraged if you do not understand them initially, but once you do you will be using the plus question parfai...
EL
Answered by Ella L. • French tutor
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use the substitution u=2+ln(x) to show that int(e,1(ln(x)/x(2+ln(x)^2))dx)=p+ln(q) , where p and q are rational numbers.

So u=2+lnx, therefore du/dx=1/x , we can work out the new upper and new lower limit by substitute in e and 1 into 2+lnx , and we get 2+ln(e)=3 , 2+ln(1)=2Rearrange the differential we get dx=xdu , substitute...
Answered by • Maths tutor
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Solve the quadratic inequality: x^2 - 5x + 4 < 0

x 2 -5x+4 &lt;0First we ignore the inequality and try to solve the equation x 2 -5x+4=0, which we do via factorising (x-4)(x-1)=0. x = 4 or x=1We draw the graph using our solution, going through the points o...
HH
Answered by Hariz H. • Maths tutor
13687 Views

Solve the following simultaneous equations to find x and y.

2x 2 - 2y = 282y - 4 = 12x y - 2 = 6xy = 6x + 2 Substitute y = 6x + 2 2x 2 - 2(6x + 2) = 282x 2 - 12x - 4 = 282(x 2 - 6x - 2) = 28x 2 - 6x - 2 = 14x 2 - 6x - 16 = 0(x - 8)(x + 2) = 0 if x = 8 then y = 50if x...
PD
Answered by Prahlad D. • Maths tutor
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