<p>With such a variety of questions, GCSE Maths can be a real headache for students. In individual sessions with a GCSE Maths tutor you can focus on exactly the topics you need help with. In our online classroom, tutors use diagrams, graphs and illustrations to enhance their lessons.</p>
<p>From algebra to indices, <strong>they will explain concepts at your own pace and in new ways so that you fully understand them.</strong> So when your GCSE exams come round, you'll be able to tackle even the most difficult questions on the paper.</p>

- Recent experience
- Proven exam success
- Strong communication skills
- Personally interviewed
- A or A* in their subjects
- Up-to-date syllabus knowledge

I cannot praise this tutor enough. Highly skilled in mathematics, teaches at the student's pace, patient and super efficient. A conscientious person who responds immediately to messages. The lesson was tailor made to suit my own needs. Mayur is excellent at pin pointing math problems quickly - taking things back to basic principals where needed. A most enjoyable tutorial - I would highly recommend this very gifted tutor to students of every ability.

Elizabeth, Student

Jonny is a 5 star tutor and has gone out of his way to help us at times when things haven't gone quite to plan. His knowledge, patience and delivery of problem solving is excellent. I totally recommend Jonny from our experience of him a my son's math's tutor. Thanks Jonny!

Emma, Parent from Cornwall

Fantastic help. I was struggling with three questions and I knew, just my luck, these type of questions will be on the text. Neha was able to give me a last minute late evening lesson, and explained thoroughly and clearly what I needed to do. I had a test the next day and got 43 out of 45. Yeh!!! Thanks Neha! Austin

Sheila, Parent from Genève

Jack has been tutoring my 12 year old son for about 2 months now and is really beginning to improve his confidence and mathematical ability. The lessons are fun and very thorough, often reinforcing a topic covered in classwork or tricky homework, leaving him confident and ready to move on to the next one. Unlike in school, during sessions with Jack my son is never afraid to say when he doesn't fully understand something, ensuring 100% confidence in a topic. Jack has been very flexible with the timings of our sessions and has endless patience. This is a great way to sign up to a tutor and if you are lucky enough to have Jack you will not be disappointed.

Julia, Parent from Hampshire

Why limit yourself to someone who lives nearby, when you can choose from tutors across the UK?

By removing time spent travelling, you make tuition more convenient, flexible and affordable

We've combined live video with a shared whiteboard, so you can work through problems together

All your Online Lessons are recorded. Make the most out of your live session, then play it back after

Usually we cover both subject knowledge and exam technique, although that can change depending on each individual student. Then we go through diagrams, and they ask questions, and we go from there.

Lots of students say that the classes are too big in school, or that they don't have time to ask teachers after Online Lessons. In my Online Lessons, we take time to explore things in a little in a bit more detail.

I always look up the board my students are taking so the Online Lessons are really relevant. Then we go through past papers or set texts, whatever the student finds helpful.

I use the shared whiteboard. We make diagrams together and label them, and often the student prints it off because they know it's right and they completely understand it.

After tutoring one girl went and told all her friends the new explanation I gave her. And she was so excited about what she wrote in the exam she emailed me immediately afterwards.

There was one girl who had her exam on Monday. She wanted tuition on Friday, Saturday and Sunday beforehand. It was very intense, but she said the exam went well.

Like all equations, you're going to start off by getting all the x's on the same side of the = side and all the rest on the other side. So we start off with 7x-14=4x+7. Moving the x's to one side means that we have to subtract 4x from both sides, which means we end up with 7x-4x-14=4x-4x+7 which is 3x-14=7. Then we move all the rest to the right hand side which means adding 14 to both sides, ending up with 3x=21. The last step is to divide by 3 to get the 3x to change into x (which is 1x). This means we end up with x=7.

The easiest way to solve a simultaneous equation is by the method of substitution.
First of all, we take the first equation, and rearrange it so that it is in terms of y. Or, in other words, rearrange it so that it becomes y=something, as shown below.
3x+2y=36
Subtracting 3x from both sides and then dividing both sides by 2 gives us:
y=18-1.5x
We then substitute this into the second equation, in place of y. Giving us:
5x+4(18-1.5x)=64
Multiplying out of the brackets gives us.
5x-6x+72=64
Which, with simplification, and 72 subtracted from both sides, gives us:
-x=-8 which is the same as x=8.
Then, all we need to do in put this value of x into either of the original equations, giving us y=6.

The probability of picking a ball from a bag is the number of balls of that colour divided by the total number of balls.
Therefore in the first instance, the probability of a red ball is 3/9 or 1/3rd.
If that ball is now removed the probability of picking a 2nd is 2/8 or 1/4.
Therefore the probability that both these happen is 1/4 * 1/3 which is 1/12.

First Step: - {-2[x-3y+12]-5z-30}
Second Step: - {-2x+6y-24-5z-30}
Third Step (Order is x,y, then z) : - {-2x+6y-5z-54}
Final Step: 2x-6y+5z+30

Step 1: Multiply both equations together so that the multiples of one of the unknown terms are the same or the negative of that number. This will allow you to add/subtract the two equations to eliminate one of the unknowns. Remember you are multiplying the whole of the equation so each term must be mutliplied.
Step 2: once you have eliminated one of the unknown terms (e.g. y) you can easily solve the equation to find the other unknown term (e.g. x) by rearraning the equation to make it the subject .
Step 3: Once you have found one of the unknowns, you can substitue your answer into one of the equations, and solve the equation to find the answer to the other unknown.

Answered by Matthew K.

Studies MBBS at Kings, London

x=4
y=3

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Time: | 2018-02-20T13:06:53Z |