Why limit yourself to someone who lives nearby, when you can choose from tutors across the UK?

By removing time spent travelling, you make tuition more convenient, flexible and affordable

We've combined live video with a shared whiteboard, so you can work through problems together

All your tutorials are recorded. Make the most out of your live session, then play it back after

Usually we cover both subject knowledge and exam technique, although that can change depending on each individual student. Then we go through diagrams, and they ask questions, and we go from there.

Lots of students say that the classes are too big in school, or that they don't have time to ask teachers after lessons. In my tutorials, we take time to explore things in a little in a bit more detail.

I always look up the board my students are taking so the lessons are really relevant. Then we go through past papers or set texts, whatever the student finds helpful.

I use the shared whiteboard. We make diagrams together and label them, and often the student prints it off because they know it's right and they completely understand it.

After tutoring one girl went and told all her friends the new explanation I gave her. And she was so excited about what she wrote in the exam she emailed me immediately afterwards.

There was one girl who had her exam on Monday. She wanted tuition on Friday, Saturday and Sunday beforehand. It was very intense, but she said the exam went well.

Start the integration by parts process
**|udv = uv - |vdu**
u = (ln x)^{2} dv = x^{7} dx
du = 2(ln x)/x dx v = 1/8 x^{8}
= 1/8 x^{8} (ln x)^{2} - | 1/4(ln x)x^{7} dx
= 1/8 x^{8} (ln x)^{2} -1/4 | x^{7}(ln x) dx
Repeat the integration by parts method on the integral |x^{7}(ln x) dx
u=(ln x) dv = x^{7} dx
du = 1/x dx v = 1/8 x^{8}
= 1/8 (ln x) x^{8} - 1/8 | x^{7} dx
= 1/8 (ln x) x^{8} - 1/64 x^{8}
Simplify the answer (remebering to add the constant of integration).
= 1/8 x^{8} (ln x)^{2} -1/4 (1/8 (ln x) x^{8} - 1/64 x^{8 })
= **1/8 x**^{8} (ln x)^{2} -1/32 (ln x) x^{8} + 1/256 x^{8} + C

Answered by Rowan D.

Studies Astronomy and Phyiscs at Glasgow

Draw any right triangle with angle x in one of the corners. This is the key to properly understanding trigonometry: start by sketching the problem. Whenever you see cosine and sine, your first thought ought to be a triangle. Now, define the hypothenuse to be of length 1. The leg adjacent to the angle x will then have length cos(x), and the leg opposite the angle will have length sin(x) — this is one way cosine and sine are defined. Recall that the Pythagorean Theorem states that “a^{2} + b^{2} = c^{2}”, where a and b are legs and c is the hypothenuse. In this problem, we have “a=cos(x)”, “b=sin(x)”, and “c=1”. Now, we substitute those back into the Pythagorean Theorem to get “cos(x)^{2} + sin(x)^{2} = 1^{2} = 1”. Done.

1. Differentiating left hand side: 2(x+y)(1+dy/dx) from the chain rule
2. Differentiating right hand side: y^{2}+2xy(dy/dx) from the product rule
3. Equating sides and taking out factors of dy/dx to rearrange for dy/dx:
dy/dx=[y^{2}-2(x+y)]/[2(x+y)-2xy]
4. Substitute x=1 into original expression and solving for y (i.e. solving (1+y)^{2}=y^{2}) gives y=-1/2
5. Substituting x=1 and y=-1/2 into the expression for dy/dx gives dy/dx=-3/8

f(x) = 3x^3 + 2x^2 - 8x + 4
f(2) = 3(2)^3 + 2(2)^2 - 8(2) + 4
f(2) = 3(8) + 2(4) - 8(2) + 4
f(2) = 24 + 8 - 16 +4
f(2) = 20

We integrate by parts:
u=x u'=1; v'=sin(x) v=-cos(x)
integral(x*sin(x)dx) = -x*cos(x) + integral(cos(x)dx) = -x*cos(x) + sin(x) + C
where C is a constant.

The general method for (a+b)^n is: 1)write out pascals triangle (see whiteboard) and stop at the nth row. Write this on a line. 2)write down the powers of a in ascending order (and simplify) 3)write down the powers of b in descending order (and simplify) 4)multiply the first number in your 3 lines, then the second number and so on and simplify each term 5)add each term
Example expand (1+3x)^{3}
1
1 1
1 2 1
1 3 3 1
The relevant line of pascals triangle is 1,3,3,1. The powers of 1 in ascending order are just 1,1,1,1. The powers of 3x in descending order are
(3x)^{0}=1,(3x)^{1}=3x,(3x)^{2}=9x^{2},(3x)^{3}=27x^{3}
Our four terms are then:
1*1*1=1,3*1*(3x)=9x, 3*1*(9x^{2})=27x^{2}, 1*1*(27x^{3}）=27x^{3}
So the expansion is 1+9x+27x^{2}+27x^{3}

Company information

Popular requests

Are you there? – We have noticed a period of inactivity, click yes to stay logged in or you will be logged out in 2 minutes

Your session has timed out after a period of inactivity.

Please click the link below to continue (you will probably have to log in again)

mtw:mercury1:status:ok

Version: | 3.49.3 |

Build: | d44f18974ed8 |

Time: | 2017-08-17T14:08:28Z |

Your message has been sent and you'll receive an email to let you know when responds.

Tutors typically reply within 24 hours.

Tutors typically reply within 24 hours.

Thanks , your message has been sent and we’ll drop you an email when replies. You should hear back within 24 hours.

After that, we recommend you set up a free, 15 minute meeting. They’re a great way to make sure the tutor you’ve chosen is right for you.

Thanks , your message has been sent and we’ll drop you an email when replies. You should hear back within 24 hours.

After that, we recommend you set up a free, 15 minute meeting. They’re a great way to make sure the tutor you’ve chosen is right for you.

**Limit reached ***(don't worry though, your email has still been sent)*

Now you've sent a few messages, we'd like to **give the tutors a chance to respond**.

Our team has been notified that you're waiting, but please contact us via

support@mytutor.co.uk or **drop us a call on +44 (0)203 773 6020** if you're in a rush.

**Office hours are 8am to 7pm**, Monday to Friday, and we pick up emails on weekends.

Thanks,

The MyTutor team

**Limit reached ***(don't worry though, your email has still been sent)*

Now you've sent a few messages, we'd like to **give the tutors a chance to respond**.

Our team has been notified that you're waiting, but please contact us via

support@mytutor.co.uk or **drop us a call on +44 (0)203 773 6020** if you're in a rush.

**Office hours are 8am to 7pm**, Monday to Friday, and we pick up emails on weekends.

Thanks,

The MyTutor team

**Limit exceeded ***(Your message will not be sent)*

You should have recieved a notification with your previous message, and **our team have also been notified that you're waiting.**

If you're in a rush, please contact us via support@mytutor.co.uk or **drop us a call on +44 (0)203 773 6020** .

**Office hours are 8am to 7pm**, Monday to Friday. We also pick up emails on weekends.

Thanks,

The MyTutor team

**Limit exceeded ***(Your message will not be sent)*

You should have recieved a notification with your previous message, and **our team have also been notified that you're waiting.**

If you're in a rush, please contact us via support@mytutor.co.uk or **drop us a call on +44 (0)203 773 6020** .

**Office hours are 8am to 7pm**, Monday to Friday. We also pick up emails on weekends.

Thanks,

The MyTutor team

If you're taking A-Level Maths - well done to you. It's one of the trickier A-levels but also one of the most well respected, and it will set you up for all sorts of career paths. That said, it can be a surprising jump up from the Maths you've done before. And because the course progresses so quickly, it's easy to feel like you're getting left behind.

With one-to-one online support from a Maths tutor, you can spend time focusing on the topics you want to work on.Whether it's differentiation that's got you in a pickle, or logarithms that are giving you trouble, our tutors are on hand to help. So by the time it comes round to your exams, you'll feel confident, well prepared, and able to achieve the results you want.