An electrical heater supplies 500J of heat energy to a copper cylinder of mass 32.4g Find the increase in temperature of the cylinder. (Specific heat capacity of copper = 385 J*kg^-1*Celsius^-1
The temperature of a body of mass m and specific heat capacity c rises by change in temperature (delta)T when an amount of heat Q is added to it (Q = mc(delta)T). From the equation we see that the change in temperature is simply equal to the heat divided by the mass times the specific heat capacity of copper ((delta)T = Q / m*c). Now we can just plug in the numbers to find the answer. (Note that the mass is not given in SI units and we have to convert it 32.4g = 0.0324kg). From here follows that the increase in temperature is equal to 500 / 0.0324 * 385 or 40.0834, which we can round to 40.1 degrees Celsius.
VB
Related Physics A Level answers
All answers ▸A ball is thrown in the air with velocity of 50.0 m/s, assuming no air resistance calculate its maximum height.
If a ball of mass 5kg is dropped from rest, how far will it travel in the 3 seconds after it reaches 150m from it's original position? Write down the change in it's total energy after the 3 seconds. (ignoring air resistance)
What is the quark composition of a proton?
A box initially at rest is on a plank, of length 5m, that is elevated at an angle such that tan(a)=3/4. When it reaches the end of the plank it has velocity 5ms^-1. Calculate the average frictional force on the box.