In the Photoelectric effect, Why does increasing the light intensity have no effect on the energy of the electron emitted?

The equation to calculate the energy of an emitted electron is: E = hf - φ, where E is the energy of the electron emitted, is the Planck's constant, f is the frequency of the light and φ is the work function of the metal which is the minimum energy required to emit an electron. Here you can see that nothing is dependant on light intensity because the intensity is essentially the number of photons and does not increase nor decrease the energy of a single photon, therefore has no effect on the energy of an electron emitted. 

If the light has enough energy to emit a photon i.e. has a high enough frequency, then the light intensity will increase the probability of an electron being emitted from the metal.  

Answered by Pankaj K. Physics tutor

15791 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

What is the De Broglie wavelength of an electron given it has a kinetic energy of 1 eV? You are given the mass of an electron is 9.11x10^-31 kg and Planck's constant is 6.63x10^-34


A rocket travels with constant velocity in a straight line in deep space. A ball is thrown from the back to the front (ie from the thrusters to the nose). Describe the path of the ball. Describe the path if the rocket were accelerating along this line.


Explain how a standing wave is formed


Alex's rocket lands after 4.56s and Billy's lands after 5.21s. What was the initial (maximum) vertical velocity of both of their rockets as they left the launchpad to 3s.f.?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy