How many joules of heat energy are required to raise the temperature of 10kg of water from 22⁰C to 27⁰C? (The Specific Heat Capacity of water is 4200 Jkg^-1⁰C^-1)

Heat energy Q = mass of substance m X SHC of substance C X change in temperature ΔT Q = 10kg X 4200Jkg^-1⁰C^-1 X (27-22)⁰C Q = 10kg X 4200Jkg^-1⁰C^-1 X 5⁰C Q=210,000J = 210kJ 210 kilojoules of energy is required

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Answered by Jordan S. Physics tutor

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