Find the solution of 3^{4x} = 9^{(x-1)/2}.
First, recognise that 3^2 = 9. Recall the rule for multiplying indices, that (a^b)^c = a^{bc}. Then, substitute 3^2 in place of 9 to get 3^{4x} = (3^2)^{(x-1)/2}. Use the rule for multiplying indices, so that the equation is now 3^{4x} = 3^{x-1}. This implies 4x=x-1, and therefore 3x = -1, and finally, x = -1/3 is the solution.
CO
Answered by Charles O. • Further Mathematics tutor
2699 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Prove that sin(x)^2 - 5cos(x)^2 = 6sin(x)^2 - 5
Can you explain induction and go through an example?
Given y=x^3-x^2+6x-1, use diffferentiation to find the gradient of the normal at (1,5).
Find the gradient of the line x^2 + 3x - 6 at the point (5,34)