Photons with 605 THz frequency strike metal of 1.2eV work function. Calculate the maximum energy of photoelectrons and their velocity. What amount of energy is necessary to stop all photoelectrons? (Planck's constant. electron mass and charge are given)

Start off by converting all given data into SI units to avoid confusion later on. The photoelectric effect happens when photons with energy larger than work function strike metal, thus releasing the electrons from it. Write down the formula for photoelectric effect and check if all terms are understood: KE = E(photons) - W = hf - W (W- work function, KE- kinetic energy, f- frequency of photons). Put in the values to find kinetic energy: KE = 2.0810^-19 J. For velocity just adjust the kinetic energy formula from KE=(mv^2)/2 to v=(2KE/m)^1/2. Plug in the values and find the velocity v = 675752.2 m/s. As for the last part, it is enough to use the same amount as maximum kinetic energy to completely stop all photoelectrons. The stopping energy must be higher or equivalent to the photoelectron energy.

IV
Answered by Ignas V. Physics tutor

2575 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

How deep is the water if it takes a pulse of ultrasound 0.8s to be received back at the boat. the speed of ultrasound is 1600m/s in water


A car of mass 1000 kg is travelling at 15 m/s. The driver applies the brakes for 4 seconds, slowing the car to 5 m/s. What is the average power output of the brakes over the 4 seconds? Assume there are no other forces acting on the car.


A charged particle in a cyclotron moves in a circle with radius 5mm. If the field in the cyclotron is 0.06 T and the velocity of the particle is 2.4x10^7, what is the charge-mass ratio of the particle?


When a toothbrush is charging, p.d. across the primary coil is 230 V, p.d. across the secondary coil is 7.2 V. The primary coil in the charging base has 575 turns of wire on its coil. Find the number of turns on the secondary coil inside the toothbrush.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning