A baby in a bouncer bounces up and down with a period of 1.2s and amplitude of 90mm. Calculate the baby's maximum velocity.
Relevant equations: 1) frequency = 1/ time period; 2) v(max) = Amplitude*(2pifrequency)
First, we need to calculate the frequency of the baby's oscillation. That is, the number of times, per second, that the baby moves up, then down, and back to their original position. We do this by substituting the values into equation 1. Then, we use that value in equation 2 to find the speed at which the baby moves fastest - their maximum velocity. They will travel at this speed when moving through their original position when their acceleration is zero.
SH
Related Physics GCSE answers
All answers ▸When a force is applied to a spring, the spring extends by 12cm. The spring has a spring constant of 25 N/m. Calculate the force applied to the string in N.
Two cars are crash tested. Car A has a crumple zone, B doesn't. Both cars have mass 1500kg and a driver of mass 80kg and crash at 20m/s. Cars A and B take 0.8 and 0.2 seconds to stop respectively. Using this information, are crumple zones a necessity? (6)
What is the equation of an accelerated body moving in one dimension?
A cup of boiling water (100 degrees C) (0.2kg) transfers 20 000J of heat to its surrounding in 1 hour. What temperature is the water in the kettle after 1 hour?