Integrate x^2sin(x) between -pi and pi
It is possible to solve this question using integration by parts. However, we note that sin(x) is an odd function, meaning that sin(-x) = -sin(x). Thus x2sin(x) is also an odd function. This means that the area under x2sin(x) from 0 to pi is equal to the area under x2sin(x) from -pi to 0. Hence the integral of x2sin(x) between -pi and pi is 0.
HL
Answered by Harry L. • Further Mathematics tutor
8103 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸Using the substitution u = ln(x), find the general solution of the differential equation y = x^2*(d^2(y)/dx^2) + x(dy/dx) + y = 0
how do I do proofs by induction?
How do I determine whether a system of 3 linear equations is consistent or not?
Calculate: ( 2+i√(5) )( √(5)-i).