Integrate x^2sin(x) between -pi and pi
It is possible to solve this question using integration by parts. However, we note that sin(x) is an odd function, meaning that sin(-x) = -sin(x). Thus x2sin(x) is also an odd function. This means that the area under x2sin(x) from 0 to pi is equal to the area under x2sin(x) from -pi to 0. Hence the integral of x2sin(x) between -pi and pi is 0.
HL
Answered by Harry L. • Further Mathematics tutor
8038 Views
See similar Further Mathematics A Level tutorsRelated Further Mathematics A Level answers
All answers ▸The cubic equation 27(z^3) + k(z^2) + 4 = 0 has roots α, β and γ. In the case where β=γ, find the roots of the equation and determine the value of k
Differentiate x = sinhy with respect to x
How do I solve x^2 + x - 6 > 0 ?
How do you find the matrix corresponding to a transformation?