A 10kg cube of iron with length 5cm is resting on a table surface. Assuming the acceleration under gravity of the block is 9.81ms^(-2), what is the pressure on the table?
Pressure is given by P=F/A, where F is force and A is area. Neither are given in the question, but A is the area of the cube in contact with the table; this is the area of one face of the cube, so A=LL=0.050.05=0.0025 m2 (Side Note - Remember to convert to meters!).
Now we have A, we need F - this is given by F=ma, which is F=10*9.81=98.1 N.
Finally, P=F/A=98.1 N/0.0025 m2= 39240 Pa. (Side Note - 1 Pa=1 N/1 m2)
WH
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