Solve x^3=1 giving all the roots between -pi<=theta<=pi in exponential form

 x^3=1=e^2(pi)i

x=e^2(pi)ik/3

The three roots are

k=0    x=1 

k=1    x=e^2(pi)*i/3

k=-1   x=e^-2(pi)ik/3

AA
Answered by Anmol A. Further Mathematics tutor

2375 Views

See similar Further Mathematics A Level tutors

Related Further Mathematics A Level answers

All answers ▸

Integrate xcos(x) with respect to x


What is the modulus of 3+4i?


Evaluate ∫sin⁴(x) dx by expressing sin⁴(x) in terms of multiple angles


Find the values of x where x+3>2/(x-4), what about x+3>2/mod(x-4)?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences