A ball is thrown in the air with velocity of 50.0 m/s, assuming no air resistance calculate its maximum height.

Use SUVAT equations to find height, S, when final velocity, V, is 0: s = ?u = 50 m/sv = 0 m/sa = -9.81 m/st = Not necessaryRecall: v^{2} = u^{2} +2as s = -u^{2}/(2a) = -2500/(2 x -9.81) = 127.4 m But given to 3 sig figs so s = 127 m