A 6.0W bulb is connected to a source of 480J of energy. Assuming the system is 100% efficient, and the bulb runs at full power, how long can it stay lit?

  • Bulb power = 6.0W - Energy provided = 480J - Use equation P = E / t (Power = energy/time) where power is in watts, energy is in joules, and time is in seconds - Rearrange the equation to give t = E / P (time = energy/power) to find the time in seconds - Plug in the values to give t = 480/6 = 80 - Therefore time = 80 seconds.
LW
Answered by Lily W. Physics tutor

3464 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

A ball of mass 1kg is rolled down a hill of height 10m. At the bottom it collides with another ball of mass 5kg. What speed does the second ball move away with? You can assume the collision between the balls is elastic.


The energy transferred from the water in the kettle to its surroundings in 2 hours is 46 200 J. The mass of water in the kettle is 0.50 kg. The specific heat capacity of water is 4200 J/kg °C. What is its temperature after 2 hours?


What is the difference between a transverse and longitudinal wave?


How to remember what is Ideal Gas Law?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences