t=−3 , find t^2−2t−1
we need to substitute the value of 't' in the equation. we are given the value of 't'. it is equal to 3. Now, substitutting 3 in the place of 't' within the equation gives:
(3)^2 - 2(3) - 1
= (3 x 3) - (2 x 3) - 1
= 9 - 6 - 1
= 2
Therefore, when 't' = 3, t^2-2t-1 = 2
DP
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