Draw the full curly mechanism for the reaction between Bromo-Methane and NaOH. What reaction is it?
The negatively charged OH group attacks the backside of the Bromo-Methane (backside in the sense that it is the opposite side to which Bromine is bonded).
A transition state consisting of a central Carbon atom with five groups bonded to it, is created - it is important to denote this to be a transition state. The Bromine leaves the transition state to leave a Methanol molecule.
It is an Sn2 reaction
BB
Related Chemistry IB answers
All answers ▸What is a dative covalent bond?
What's the difference between Bronsted-Lowry acids and Lewis acids?
Use the following information: [[[[2H2(g) + O2(g) → 2H2O(l) ∆H = −572 kJ mol−1]]]] [[[[2H2(g) + O2(g) → 2H2O(g) ∆H = −484 kJ mol−1]]]] to calculate the enthalpy change for the process: H2O(g) → H2O(l)
Describe and compare three features of the structure and bonding in the three allotropes of carbon: diamond, graphite and C60 fullerene.