Draw the full curly mechanism for the reaction between Bromo-Methane and NaOH. What reaction is it?
The negatively charged OH group attacks the backside of the Bromo-Methane (backside in the sense that it is the opposite side to which Bromine is bonded).
A transition state consisting of a central Carbon atom with five groups bonded to it, is created - it is important to denote this to be a transition state. The Bromine leaves the transition state to leave a Methanol molecule.
It is an Sn2 reaction
BB
Related Chemistry IB answers
All answers ▸Which compound is a member of the same homologous series as 1-chloropropane? A. 1-chloropropene B. 1-chlorobutane C. 1-bromopropane D. 1,1-dichloropropane
Describe how sigma and pi bonds form and describe how single and double bonds differ.
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What is the ionisation energy trend as we go down the group and across the period?