How to calculate temperature of expanded ideal gas.

By definition an ideal gas in a closed follows the relationship of PV=nRT, or PV/T = constant

This means that Pressure * Volume/ Temperature will be the same at the start and end of the process. 

So P1V1/T1=P2V2/T2

Assuming that we have a gas at a temperature of 300k (T1) in a piston initially at 1m(V1) which is then expanded at constant pressure (isobaric) to 2m3.(V2) What would be the final temperature?

As Pressure is the same at the start and end of the process, we can ignore the pressure terms, giving

V1/T1=V2/T2

Rearranging the equation to give a solution to T2

T2=V1*T1/V2

Thus filling in the terms we already know, gives

T2=1*300/2

T2=150k

Answered by Iain C. Physics tutor

5583 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

Two beakers contain water at room temperature. One contains 200ml, the other 400ml. If both beakers are heated above identical Bunsen burners, which of the two will take longer to boil?


A car driver has to make an emergency stop. The braking distance depends on the speed of the car. For the same braking force, what happens to the braking distance if the speed doubles?


A person swims from a depth of 0.5m to 1.7m below the surface of the sea. Denisty Sea Water = 1030 kg/m^3. g=Gravitational Field Strength = 9.8 N/kg. Calculate the change in pressure on the swimmer and give the unit.


What is the Doppler effect and how is it exploited in everyday life?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy