1 - We first need to find a common factor, something that is the same in both parts of the expression.

2 - Then we need to take this out of the expression by dividing both parts of the expression by the common factor.

3 - We then need to rewrite the expression with the common factor outside the brackets and the rest of the expression that has been divided inside the brackets.

2b²+ 6b

1 - Here both parts of the expression are divisible by 2b. Therefore the common factor is 2b.

2 - 2b² divided by 2b is b.

6b divided by 2b is 3.

3 - We now rewrite our expression with the common factor on the outside of the brackets:

2b( )

We now need to put in the expression after it has been divided by the common factor:

2b(b+3)

Solve 5x-2>3x+11

Related Maths GCSE answers

By plotting appropriate graphs, find x to the nearest integer if x^2+3=2-4x.

Expand (x-3)(x+7)

Factorise 2b^2 + 6b

Use the factor theorem to show that (x+2) is a factor of g(x)= 4x^3 - 12x^2 - 15x + 50