How to calculate the integral of sec(x)?

First of all, multiply secx by (secx+tanx)/(secx+tanx). Use the substitution u=secx+tanx, so that du=(secxtanx+sec2x) dx and then substitute both terms. Calculate the integral of the du/u arriving at ln|u|+C. Then put in the substituted function of x. The result is ln|secx+tanx|+C.

CK

Related Further Mathematics A Level answers

All answers ▸

I'm struggling with an FP2 First-Order Differential Equations Question (Edexcel June 2009 Q3) and the topic in general!


What is the polar form of the equation: x^2+y^2 =xy+1


Find the integrating factor of the following first order ODE: dx/dt = -2tx +t.


Find the values of x where x+3>2/(x-4), what about x+3>2/mod(x-4)?