Expand (2x+3)^4

We will you use Pascal's triangle in order to find coefficients:         1        1  1       1 2 1     1 3  3 1    1  4  6  4  1 so, our coefficients will be 1,4,6,4,1 now, let's expand: (2x+3)4=(2x)4+4*(2x)33+6(2x)232+4(2x)*33+34=16x4+96x3+216x2+216x+81 (2x+3)4=116x4+96x3+216x2+216x+81

CP

Related Further Mathematics GCSE answers

All answers ▸

Work out the equation of the tangent to the curve y=x^2+5x-8 at the point (2,6)


Find the coordinates of the minimum/maximum of the curve: Y = 8X - 2X^2 - 9, and determine whether it is a maximum or a minimum.


x^3 + 2x^2 - 9x - 18 = (x^2 - a^2)(x + b) where a,b are integers. Work out the three linear factors of x^3 + 2x^2 - 9x - 18. (Note: x^3 indicates x cubed and x^2 indicates x squared).


find the stationary point of the curve for the equation y=x^2 + 3x + 4