It takes 1.8s to drop a ball of a bridge. How high is the bridge and what speed is reached?
t= 1.8s
a=-9.81ms-2
v=u+at
v= -9.81 x 1.8 =17.658 m/s
s= ut + 1/2 at2 (as u is 0 s= 1/2 at2)
s = 1/2 x 9.81 x 1.82 = 15.9m
GL
t= 1.8s
a=-9.81ms-2
v=u+at
v= -9.81 x 1.8 =17.658 m/s
s= ut + 1/2 at2 (as u is 0 s= 1/2 at2)
s = 1/2 x 9.81 x 1.82 = 15.9m
