A hot air balloon is travelling at a speed of 5.0m/s at an angle of 60.0 degrees up from the horizontal. Find the vertical and horizontal components.

The diagram would have the following:

An arrow pointing upwards labeled v(y)

An arrow pointing to the right labeled v(x)

An arrow pointing in between those lines with a degree between this one and the right one labeled 60 degress.

The horizontal component v(x) would be:

v(x) = vcos(theta)=5.0cos(60)=2.5m/s

The vertical component v(y) would be:

v(y) = vsin(theta)=5.0sin(60)=4.3301m/s=4.3m/s

The horizontal component would be 2.5m/s and the vertical component would be 4.3m/s.

MB
Answered by Marta B. Physics tutor

1908 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Given a projectile is launched, from rest, at an angle θ and travels at a velocity V, what is the range and path of motion of the projectile? (Ignore air resistance.)


During take-off from earth, an astronaut of mass 76kg has an area of contact with his seat of 0.095m^2. Calculate the average pressure on the seat when the upward acceleration of the rocket is 47ms^-2


A body with speed v is projected from the surface of the earth(mass M & radius R). Find the maximum distance from the earth that this body reaches before returning back to earth, as a function of the initial speed v, M, R and the gravitational constant G


A cup of tea contains 175 g of water at a temperature of 85.0 °C. Milk at a temperature of 4.5 °C is added to the tea and the temperature of the mixture becomes 74.0 °C. What is the internal energy lost by the water? What is the mass of the milk?


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences