An electron is traveling at a velocity of 500m/s perpendicular to a uniform magnetic field. A force of magnitude 4.32 x10^(-16) N is acting on the electron, what is the magnetic flux density of the field?

F=BQv so B=F/Qv (Q is the charge of an electron, 1.6 x10-19 C) so B=4.32 x10-16 / (1.6 x10-19 x 500) = 5.4 T

CJ
Answered by Christian J. Physics tutor

1839 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

Describe how the strong nuclear force between nucleons varies with seperation of the nucleons.


With the help of a suitably labelled graph, explain what is meant by resonance of a mechanical system.


How can I describe the motion of an object falling, due to gravity, through a fluid? And when does the object reach terminal velocity?


What is the photoelectric effect and how does it provide evidence for the quantisation of electromagnetic radiation?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning