Predict the relative boiling points of propanal, butane and prop-2-en-1-ol from the highest to the lowest boiling point

In prop-2-en-1-ol, the strongest intermolecular forces acting between the molecules are hydrogen bonds. In propanal, the strongest intermolecular forces acting between molecules would be permanent dipole-dipole forces. Between butane molecules, there would just be van der Waals forces. Since hydrogen bonds are stronger than permanent dipole-dipole forces, which are in turn stronger than van der waals forces, it follows that the order of boiling points from highest to lowest is: prop-2-en-1-ol, propanal and butane.

RK
Answered by Rajan K. Chemistry tutor

31532 Views

See similar Chemistry A Level tutors

Related Chemistry A Level answers

All answers ▸

i) Write a full balanced equation for (a) the complete combustion of glucose and (b) the incomplete combustion of glucose. ii) Following from part i) suggest a reason (and explain) the difference with the product in reaction (a) and that of reaction (b).


What is a chiral carbon and optical isomerism?


0.28 g of a gaseous hydrocarbon was turned in excess oxygen. 0.88 g of carbon dioxide and 0.36 g of water were formed. The volume of 0.28 g of the hydrocarbon at 1.01 x10^5 Pa and 298 k is 123 cm^3. Work out the molecular formula of the hydrocarbon.


Types of chemical bonds


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences