Differentiate implicitly with respect to x the equation x^3*y^5+3x=8y^3+1
3x2y5+5x3y4y'+3 = 24y2y'
3x2y5+3 = (24y2–5x3y4)y'
y' = (3x2y5+3) / (24y2–5x3y4)
NG
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