Differentiate implicitly with respect to x the equation x^3*y^5+3x=8y^3+1

3x²y⁵+5x³y⁴y'+3 = 24y²y'

3x²y⁵+3 = (24y²–5x³y⁴)y'

y' = (3x²y⁵+3) / (24y²–5x³y⁴)