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Differentiate implicitly with respect to x the equation x^3*y^5+3x=8y^3+1
3x
2
y
5
+5x
3
y
4
y'+3 = 24y
2
y'
3x
2
y
5
+3 = (24y
2
–5x
3
y
4
)y'
y' = (3x
2
y
5
+3) / (24y
2
–5x
3
y
4
)
NG
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Nora G.
•
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