An electron and a proton are in any electric field E=5x10^2 V/m. What is their speed 1.0 cm after being released?

F=Eq= 5x10^2 x 1.6x10^-19 = 8x10^-17 N

Kinetic energy theory: deltaEc= Fxd =1/2mv^2

thus v= squareroot(2xFxd/m)

v(proton) = squareroot(2x8x10^-17x1x10^-2/9.1x10^-31)=1.3x 10^6 m/s

v(electron) = squareroot(2x8x10^-17x1x10^-2/1.67x10^-27)= 3.1x10^6 m/s

EH
Answered by Emma H. Physics tutor

2095 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

If a car is traveling at a speed of 10m/s. The driving force of 500N is required to keep the speed constant . What is the power supplied by the engine?


How can an object be accelerating if it does not change in speed?


Explain why the pressure exerted by a gas increases as they are heated at constant volume, with references to the kinetic theory of gases.


An object has a mass of 10kg and sits on a slope with an angle of elevation of 45 degrees. work out the reaction force of the object to the slope and the force acting down the slope. (3/4 marks)


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning