An electron and a proton are in any electric field E=5x10^2 V/m. What is their speed 1.0 cm after being released?
F=Eq= 5x10^2 x 1.6x10^-19 = 8x10^-17 N
Kinetic energy theory: deltaEc= Fxd =1/2mv^2
thus v= squareroot(2xFxd/m)
v(proton) = squareroot(2x8x10^-17x1x10^-2/9.1x10^-31)=1.3x 10^6 m/s
v(electron) = squareroot(2x8x10^-17x1x10^-2/1.67x10^-27)= 3.1x10^6 m/s
EH
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