An electron and a proton are in any electric field E=5x10^2 V/m. What is their speed 1.0 cm after being released?

F=Eq= 5x10^2 x 1.6x10^-19 = 8x10^-17 N

Kinetic energy theory: deltaEc= Fxd =1/2mv^2

thus v= squareroot(2xFxd/m)

v(proton) = squareroot(2x8x10^-17x1x10^-2/9.1x10^-31)=1.3x 10^6 m/s

v(electron) = squareroot(2x8x10^-17x1x10^-2/1.67x10^-27)= 3.1x10^6 m/s

EH
Answered by Emma H. Physics tutor

2029 Views

See similar Physics A Level tutors

Related Physics A Level answers

All answers ▸

A simple pendulum is an example of a system in Simple Harmonic Motion, using conservation laws find a) the greatest speed of the bob and b) the magnitude of speed at a height of 1.0cm above the minimum point. Given it starts at rest, at a height of 20cm.


A) Draw field lines around a positive point particle. B) How does a faraday cage prevent the people within it recieving a electric shock ?


Hydrogen has a single proton and a single electron. Find the electric potential at a distance of 0.50 * 10^(-10) (m) from the proton.


An electron falling from one energy level to another emits a photon of wavelength 550nm. What is the difference between the two energy levels?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences