A 100kg weight is placed 0.75 meters from a see-saw on the right hand side. Dan is 75kg. How far away does he have to sit from the pivot on the left hand side to have it balance?

A see-saw represents a pivot, for the see-saw to balance the moment on the left hand side has to equal the moment on the right hand side. Moment =  Force * distance Therefore the moment of the right hand side is 100kg * 10N/kg * 0.75m = 750N/m The moment of the left hand side is 75kg10N/kgdistance. So the distance = 750/(75*10) = 1 meter. 

AC
Answered by Alex C. Physics tutor

2444 Views

See similar Physics GCSE tutors

Related Physics GCSE answers

All answers ▸

At what angle does total internal reflection occur?


How Should I structure my experiment report?


A charged particle in a cyclotron moves in a circle with radius 5mm. If the field in the cyclotron is 0.06 T and the velocity of the particle is 2.4x10^7, what is the charge-mass ratio of the particle?


Which are the forms of heat you know. Explain them briefly including an example


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning