If y=x^3+9x, find gradient of the tangent at (2,1).
To find the gradient of the tangent, we can differentiate to give dy/dx=3x^2+9. We can now put in x=2 to find the gradient at (2,1): 3(2)^2+9=21. Therefore the gradient is 21 at (2,1).
AM
Answered by Angus M. • Further Mathematics tutor
3112 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸The function f is given by f(x) = SQRT(2x − 5). Work out x when f(x) = 1.2
Work out 7/(2x^2) + 4/3x as a single fraction in its simplest form.
A curve is defined by the equation y = (x + 3)(x – 4). Find the coordinates of the turning point of the curve.
Find the tangent to the equation y=x^2 -2x +4 when x=2