If y=x^3+9x, find gradient of the tangent at (2,1).
To find the gradient of the tangent, we can differentiate to give dy/dx=3x^2+9. We can now put in x=2 to find the gradient at (2,1): 3(2)^2+9=21. Therefore the gradient is 21 at (2,1).
AM
Answered by Angus M. • Further Mathematics tutor
3212 Views
See similar Further Mathematics GCSE tutorsRelated Further Mathematics GCSE answers
All answers ▸Work out the gradient of the curve y=x^3(x-3) at the point (3,17)
Can you explain induction and go through an example?
A curve is mapped by the equation y = 3x^3 + ax^2 + bx, where a is a constant. The value of dy/dx at x = 2 is double that of dy/dx at x = 1. A turning point occurs when x = -1. Find the values of a and b.
f'(x) = 3x^2 - 5cos(3x) + 90. Find f(x) and f''(x).